from Base.models import Professional , ServiceList
from Movement.models import Calendar
# from django.utils import timezone
from django.db.models import Sum


def metric(Day):
    professionals = Professional.objects.all()
    services = ServiceList.objects.all()
    # Importante: removi o .values() aqui para podermos acessar os objetos relacionados (como cliente)
    service_movement = Calendar.objects.filter(date=Day)

    professionals_report = {}

    for professional in professionals:
        professionals_report[professional.name] = {}

        for service in services:
            # Filtramos os agendamentos específicos deste profissional e serviço
            service_sum = service_movement.filter(
                professional=professional,
                service=service,
            )

            # Cálculo dos totais
            servSum = service_sum.aggregate(Sum('gross_value'))['gross_value__sum'] or 0
            servCont = service_sum.count()

            # --- NOVA PARTE: Detalhamento dos clientes ---
            # Criamos uma lista com o nome completo de cada cliente atendido
            clients_list = []
            for appointment in service_sum:
                client_name = f"{appointment.client.first_name} {appointment.client.last_name}"
                clients_list.append({
                    'name': client_name,
                    'time': appointment.time.strftime('%H:%M'),  # Opcional: mostra o horário
                    'value': appointment.gross_value
                })
            # ---------------------------------------------

            professionals_report[professional.name][service.name] = {
                'servSum': servSum,
                'servCont': servCont,
                'clients': clients_list,  # Aqui estão os detalhes que você pediu
            }

    # Cálculo do total geral simplificado
    sum_of_prof = service_movement.aggregate(Sum('gross_value'))['gross_value__sum'] or 0

    return {
        'professionals_report': professionals_report,
        'sum_of_prof': sum_of_prof,
    }